Recent content by clombard1973

Let's start with where they get V2/r from. If you want to know the distance around some part of a circle given an angle theta you can find it by using S = theta*r, take the derivative of each side to get the tangential velocity going around the circle: dS/dt = (dtheta/dt)*r = V and...

Charge, voltage and capacitance are related by the equation Q = VC, where Q is the charge on the plates of the capacitor, C is the capacitance of the capacitor, and V is the voltage dropped across the capacitor. So if you double the plate separation distance, and you know that the capacitance...

It is almost as if you are not reading what I am telling you. The equation you are using has to be set up for the experiment you are doing. You say it has values representing the position of the ball after a bounce, when? 10 seconds after a bounce? 15 seconds after a bounce, or just after a...

Hello again, Wow, I have just the opposite wish, I wish I were more like you and my friend in that I had a "feeling" about what it is I am trying to solve and then would apply the math to it. Instead I just look at everything that should be accounted for, write my mathematical model, solve...

Yeah it was a long time ago when I was in college (as a student anyway) and I can remember some of these things being confusing. I always found that, and I do not know why, analyzing something from a mathematical point of view always gave me insight into the problem as well. Most people were...

Hi there, I do like your analogy, the only thing I might add, and I am not criticizing you in anyway, is that Experiment number 3 and number 1 are word for word the same. Except at the very end of experiment 3 where you use another analogy that would be the same as a voltage increase. I agree...

The fact that B and C are almost the same, whatever units are used, is at best a coincidence. They have nothing to do with each other and are NOT related. Nonetheless diazano is correct, something is not right because this equation has been used for almost 300 years to accurately describe the...

There's nothing wrong with a very small initial position If the initial position of the ball at time t = 0 is -23.8 meters, that just means with respect to the place where the measurement of position is being taken is 23.8 meters above the spot where the ball is presumed to be when the...

Well said Yup I like it. Very descriptive in your reply, you relate each of his constants to yours and state the meaning of yours, i.e. initial position, initial velocity, gravitational acceleration on a mass here due to Earth. There really isn't anything I can add to that last reply, other...

Hi there, Yeah Diazona is correct. If you are stating that the initial velocity is B, then your equation is the equation for distance given an acceleration upon the mass, an initial velocity of the mass and some initial height of the mass. It is a very common equation used for finding the...

So you understand that an equivalent resistance with two resistors is in series with each other must really have the same current flowing through the two resistors, but you are having trouble understanding why two resistors in parallel have the same voltage dropped across them? The previous...

I think we're on the same page The thread may be closed for you, but if others keep asking questions about the problem, then why not answer them. I think myself and "Dadface" are on the same page by now anyway, but nonetheless, threads usually close when the are purposely closed, literally...

That's what I had said I said basically the same thing you just repeated, check first to make sure the weight of the mass is at least 10 times smaller than the tension felt at the origin along the string; if this is the case the answers differ by 0.5% or less. If one checks that first and...

Why not include all forces? No one had said not to consider gravity, it's what effect does it have on the final answer? Almost none, so if you know that and can justify such a statement, which I have done, then make it easier on yourself and drop unneeded terms to simplify the analysis...

Yes Obviously you didn't understand what was in the previous posts. Yes I would ignore gravity if the breaking force were 2.5 N as long as the mass on the end of the string was 0.025510 kg or lesser in mass as this would only change the final answers by 0.5%. I've been giving exams to...