Recent content by colourpalette

Thanks! I got it now! I found the net force on block 2 (m1g-m3g-friction on the second block) and then divided it by all the masses. thanks for your help!

F=-500+490=-10=ma a= -10/m ?

F1 = T1 - m1g = -m1a1 Thanks! I tried the problem again and I'm still wrong, but less wrong! haha. Can you help me out with the second equation? I think that's where I'm off.

Homework Statement Three blocks are connected on a table as shown in the figure below. [img src="[PLAIN]http://i10.photobucket.com/albums/a122/gcfanatikk/8bc365ba.png"][/PLAIN] <-- oopsies, apparently I don't know how to embed pictures, help please? The table is rough and has a coefficient...

What I was thinking was the part of the angle (or angular resolution) out of 360 degrees of the whole circle would be the same as arc distance out of the circumference of the circle. And I have the diameter, which is kind of close to the arc distance so my answer would be close. I know where I...

My main issue with this problem is the formula and how to derive it. Homework Statement The Hubble Space Telescope has a resolution of about 0.05 arc second. What is the smallest object it could see on the surface of the Moon? Give your answer in metres. Homework Equations I tried to...

Thank you!

This means the perihelion is r(comet) + r(sun)? And therefore the aphelion would be 2(semi-major axis) - perihelion. Aphelion = 2(26AU * 149 598 000 km/AU) - r(comet) - r(sun) = 7 779 096 000 km - r(comet) - 695 500 km I don't know the r(comet) but I'm assuming it would be negligible at this...

Hm.. The closest a comet can get without going through the sun would be r(comet)+r(sun), but that would mean it's touching the sun. It would have to be a little bigger than this? Am I on the right track? As the eccentricity increases, the orbit goes from being a circle to a line, so the...

Hm I'm not sure how to find this, it's not anywhere in my textbook and I've tried Googling this too. What can I do to find the smallest perihelion value?

Homework Statement Find the maximum (aphelion) distance from the Sun for extreme elliptical orbit. (Semi-Major axis = 26) Homework Equations Eccentricity = Distance between foci/Length of major axis Major Axis = 2 * Semi-Major Axis Major Axis = Perihelion + Aphelion The Attempt at a...