Recent content by coltsamuel96

everything clear now... thank you

got it now... thank you

Homework Statement Homework Equations how do u solve for v0 from these two equations 1.)A0*v0=Av and 2.)v^2=v0^2+2gh... The Attempt at a Solution the sol is v0=[2gh*A^2/(A0^2-A^2)]^1/2... but i don´t know to get it... please help

ok this is from a book, A0v0=Av(1st equation) v^2=v0^2+2gh(2nd equation) from 1st and 2nd eliminating v and solving for v0, we get vo=(2ghA^2/A0^2-A^2)^1/2...i don´t understand how we get this v0... any helps?

no i guess it should have a speed

sorry, it is volume flux rate and not volume flow rate...

[b]1. Homework Statement Tap water flowing has an cross section area of 1.2cm^2 near the tap. after a height, h=45mm the cross section becomes 0.35cm^2...find the volume flow rate of water from the tap Homework Equations g=9.8m/s^2 The Attempt at a Solution i think of using these...

thanks for the help, now i get it...

the velocity i think can be calculated with v^2/r=g... i think it has to do something with the motion of the person jogging with and against the rotation on the station...

Please help me with this problem, at a distance of 40m from the centre of a space station, is a round platform for jogging... compare the weights felt by two persons jogging at 12km/h, when one is jogging in the direction of the rotation of the space station and other in the opposite...

mass of a star... given is a binary star system, with mass m1=6*1.99*10^30kg, radius =r1, v=270km/s, orbital period, T=1.7days... the other star of the binary system(compact and dense)with mass m2, and radius r2 orbits around a same common point... (r1>r2, G=6.67*10^-11Nm^2kg^-2)...

there´s no intial velocity... only thing given is the loss of K.E... (27%)

the mass of the wagon train is 3.18*10^4kg... and the trains stick together after the collision...

hello, can someone help me with this, a wagon train of given mass collides with a passenger train at rest... the train loses 27% of kinetic energy after the collision... find the mass of the passenger train... so what i did is, i put this formula for inelastic collision,v(final)=...