Recent content by coltson

I know that (obviously). I did it as to show that I do not know how to proceed. Well, thanks for nothing then. Yes, I know that. See my first quote in this post. Well, saying that alone does not help at all. To say what kind of work might . Well, since that for ##n>2## these inequalities...

Taking the log, I have: ## lim_{n \rightarrow +\infty} e^ {\frac 1 n * ln (\frac {n^2+1} {n^7-2}) } ## If that is correct I end with ## e^ { 0 * ln (\frac \infty \infty) } ## with is not the answer.

I don't know how to rewrite it. $$ \lim_{n \rightarrow +\infty} \sqrt [n] \frac{1}{n^5}$$ becames $$ \infty^0 $$. The rest I think follows similar paths.

Homework Statement Solve the ##\lim_{n \rightarrow +\infty} \sqrt [n] \frac {n²+1} {n⁷-2} ## 3. The attempt of a solution: First I thought about using L'Hopital's rule, but the nth root makes it useless. Then I thought about to eliminate the root multiplying it by something that is one, but...

Here is. A simple typo. Should have realized that before. Because I had not thought about drawing a "rotated" square as my plane representation. And about the second picture, I also did not think about the dotted line.

I do not understand. There is three vectors and three labels, how can it not be labelled? As far as I understand, it is the one with the label "Ortho F". I also do not understand what do you mean by "heading down". Doesn't it has to be contained in the plane? How can it be heading down, since it...

Well, I don't know how to draw it, so drawing doesn't help. I can imagine what I would like to draw if I had the skill, and all I see is that the projection is a vector contained in the plane, which means it should satisfy the plane equation.

In that case, the dot product between F and a random vector contained in the plane would be equal to zero? That means that F is the normal of the plane? But in the end, what he probably wants? The projection of F over a vector contained in this plane that is perpendicular to F?

Homework Statement Being F = (1,1,-1), the orthogonal projection of (2,4,1) over the orthogonal subspace of F is: a) (1,2,3) b) (1/3, 7/3, 8/3) c) (1/3, 2/3, 8/3) d) (0,0,0) e) (1,1,1) The correct answer is B Homework Equations The Attempt at a Solution Using the orthogonal projection...