WOW you're right! Thanks!
Then the formula would be I=Io(1-e^(-Rt/L))
Io=6.3/175=0.036A
Solving for L, L=0.069H.
But why is my method wrong? and why is di/dt not (4.9*10^-3/58*10^-6)? di is 4.9*10^-3 and dt is 58*10^-6 right?
Thank you!
Ah I see. it makes sense now. I overlooked that it is root mean square and not mean root square so you that the mean of the square value and not the square root of the square values. TY!
Homework Statement
Your circuit has a resistance of 175Ω and an ideal battery with an emf of 6.3V. What value of inductor should you add to the circuit to ensure the current increase in the first 58μs is less than 4.9mA?
Homework Equations
I think
E=L(di/dt)
The Attempt at a...
Homework Statement
This is more of a conceptual problem I'm having difficulty getting my head around.
What is the difference between Iaverage and Irms for a rectified and non rectified AC circuit?
I know Iaverage=(2/π)Imax while Irms=(1/√2)Imax but I don't understand why they are...
Do not confuse your N and kg.
The bathroom scale shows weight, not mass. Why they refer to it as kg and not N i do not know.
Mass : 77/9.81 = 7.849kg
Weight with acceleration of 12m/s = 7.849 x (12 + 9.81) = 171.2 N
Homework Statement
I have attached a diagram with the question.
Homework Equations
Biot-Savart law: (μ/4π)(I/r^2)(dlxr) or (μ/4π)(q/r^2)(dvxr)
The Attempt at a Solution
My question is,
The B field can be predicted from the right hand corkscrew rule right? So the part of the...
Yes you are right, it is a lot easier to make sense of the answer if i use the point on the x axis.
Why did you use absolute value?
I used
0 = 3k/x + [(-Q)/(x-1)]
and i get the solution x = 1.5 only
thanks.
Thanks man!
Now, I'm just curious, but if I wanted to find the spot where V=0, I would have
0=3Q/(1+r) + (-Q/r)
so r=1/2
Does that mean V=0 at x=1.5 or V=0 at both x=1.5 and x=0.5?
I think it is the second one as all potential lines have to form a closed surface.
Am I right?
thank you.