Recent content by connor02
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Find Inductor Value to Limit Current Increase in Circuit
Ah, I see, thank you NascentOxygen!- connor02
- Post #5
- Forum: Introductory Physics Homework Help
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Find Inductor Value to Limit Current Increase in Circuit
WOW you're right! Thanks! Then the formula would be I=Io(1-e^(-Rt/L)) Io=6.3/175=0.036A Solving for L, L=0.069H. But why is my method wrong? and why is di/dt not (4.9*10^-3/58*10^-6)? di is 4.9*10^-3 and dt is 58*10^-6 right? Thank you!- connor02
- Post #3
- Forum: Introductory Physics Homework Help
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AC current, conceptual question, the difference between Iaverage and Irms?
Ah I see. it makes sense now. I overlooked that it is root mean square and not mean root square so you that the mean of the square value and not the square root of the square values. TY!- connor02
- Post #3
- Forum: Introductory Physics Homework Help
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Find Inductor Value to Limit Current Increase in Circuit
Homework Statement Your circuit has a resistance of 175Ω and an ideal battery with an emf of 6.3V. What value of inductor should you add to the circuit to ensure the current increase in the first 58μs is less than 4.9mA? Homework Equations I think E=L(di/dt) The Attempt at a...- connor02
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- Current Inductor
- Replies: 4
- Forum: Introductory Physics Homework Help
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AC current, conceptual question, the difference between Iaverage and Irms?
Homework Statement This is more of a conceptual problem I'm having difficulty getting my head around. What is the difference between Iaverage and Irms for a rectified and non rectified AC circuit? I know Iaverage=(2/π)Imax while Irms=(1/√2)Imax but I don't understand why they are...- connor02
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- Ac Ac current Conceptual Current Difference
- Replies: 2
- Forum: Introductory Physics Homework Help
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The weight of an astronaut during take off?
The common bathroom scale does not divide by 9.81. It shows N. And for someone standing on the scale, this is the person's weight.- connor02
- Post #10
- Forum: Introductory Physics Homework Help
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The weight of an astronaut during take off?
No your answer is right, the scale shows 171.2. However, the unit in your answer should be N not kg.- connor02
- Post #8
- Forum: Introductory Physics Homework Help
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The weight of an astronaut during take off?
Do not confuse your N and kg. The bathroom scale shows weight, not mass. Why they refer to it as kg and not N i do not know. Mass : 77/9.81 = 7.849kg Weight with acceleration of 12m/s = 7.849 x (12 + 9.81) = 171.2 N- connor02
- Post #6
- Forum: Introductory Physics Homework Help
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What is the Biot-Savart Law and How is it Used to Calculate Magnetic Fields?
Ah i see. Aite, thank you.- connor02
- Post #3
- Forum: Introductory Physics Homework Help
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What is the Biot-Savart Law and How is it Used to Calculate Magnetic Fields?
Homework Statement I have attached a diagram with the question. Homework Equations Biot-Savart law: (μ/4π)(I/r^2)(dlxr) or (μ/4π)(q/r^2)(dvxr) The Attempt at a Solution My question is, The B field can be predicted from the right hand corkscrew rule right? So the part of the...- connor02
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- Biot-savart Biot-savart law Law
- Replies: 2
- Forum: Introductory Physics Homework Help
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Electric field = 0 at what point on x axis?
Yes you are right, it is a lot easier to make sense of the answer if i use the point on the x axis. Why did you use absolute value? I used 0 = 3k/x + [(-Q)/(x-1)] and i get the solution x = 1.5 only thanks.- connor02
- Post #15
- Forum: Introductory Physics Homework Help
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Electric field = 0 at what point on x axis?
Thanks man! Now, I'm just curious, but if I wanted to find the spot where V=0, I would have 0=3Q/(1+r) + (-Q/r) so r=1/2 Does that mean V=0 at x=1.5 or V=0 at both x=1.5 and x=0.5? I think it is the second one as all potential lines have to form a closed surface. Am I right? thank you.- connor02
- Post #13
- Forum: Introductory Physics Homework Help
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Electric field = 0 at what point on x axis?
WOW i feel STUPID. r=-0.366 or 1.366 Since x is to the right of the -1C charge, x = 2.366 when E=0. I hope i am right now.- connor02
- Post #11
- Forum: Introductory Physics Homework Help
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Electric field = 0 at what point on x axis?
my bad. r=distance to the right of the -1C charge. x=1.707 is the point on the x-axis where E=0. right?- connor02
- Post #8
- Forum: Introductory Physics Homework Help
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Electric field = 0 at what point on x axis?
r=the point on the x-axis where the E firld is 0 right?- connor02
- Post #6
- Forum: Introductory Physics Homework Help