Recent content by connor8771

Thank you, I couldn't figure that out for the life of me. You're correct, dealing with circuits drawn in odd configurations often throws me off.

Oh, the first path is in parallel with the second. Guess I didn't see it that way. So if the capacitance of the first path = C1. And the capacitance of the second path is 1/C=1/C2+1/C3 = (C3+C2)/(C2*C3) so C = C2*C3/(C2+C3). Then you would add the capacitances for the two since they are in...

The other path would be A-B-C. In which case 1/C = 1/2+1/2 = 1 so C = 1 microfarad. I thought about this. It gives the same answer as the first direction, but only by chance. In a more generalized case, 1/C1 would not necessarily equal 1/C2+1/C3. So the two paths would give different values...

Well evidently they are connected in series, so the total capacitance of the entire network could be calculated as 1/C = 1/C1 + 1/C2 + 1/C3... but that would be for the entire network. From A to C, there is only 1 capacitor, so wouldn't it just be the capacitance of that one?

Hi, I'm struggling with this question. I feel like I don't even know where to begin. It seems to be a relatively simple calculation, but would the effective capacitance between A and C not just be 1 microFarad? Obviously that can't be the correct answer because such a simple observation wouldn't...

Alright, that was a lot easier than I made it out to be. Thank you for all the help.

I know the distance from q2 has to be sqrt(2) times the distance from q1 and also that the distance from q2 has to be the distance from q1 + sqrt(1.25). I think.

It has to be in quadrant 3, if it was between it would simply be pulled towards the negative charge and if it was beyond q2 the repulsive force would outsize the attractive force at all distances.

No, they could not, and I'm starting to see that it should have been rather easy to prove that it can't exist outside of that line. So if they must exist along this line, then the vector from q1 to e must be of the form (x,x/2) and the vector from q2 to e must be of the form -(x,x/2). r1 must...

Yes, I have, but I haven't found any nice geometric feature. If the equilibrium position(s) is along the line connecting the two charges then the force vectors will be equal and opposite, and I assume that that is the case, but I haven't found a way to prove that equilibrium positions can't...

I seem completely lost at this. I barely know where to begin. I know that the forces will sum to 0 but the vectoral nature of the question is really confusing me. Best I have is that the distance between e and q2 has to be sqrt(2) times the distance between e and q1. I don't know where to go...