Recent content by cookiemnstr510510

The test case for the block of code below is: y0=10, f=@(t,y) -0.5*y, [t,y]=euler_method_attempt(f,0,5,y0,10) This code below works and is the correct answer, but I am confused on some parts of it. When indexing the for loop it seems as if the first output for "y" would be y(2), not y(1). And...

Hello @Chestermiller I really like your explanation and I can follow this formula each time. Will your method always work? Or does it depend on different books conventions? Thanks a bunch! Have a great day

I am a bit confused on the definition/convention of work. In some books I see statements that say : "If work is done on the system, its sign is positive. If work is done by the system, its sign is negative." And in other books I see things like: "By convention, work is regarded as positive...

Hello All, I wanted some insight on my answer to this problem. Lets say we have the reaction PCl3(g) + Cl2(g) ↔PCl5(g) ΔH0=-111KJ So for this reaction we know it is exothermic (because my textbook told me). But I want to make sure I understand why it is. If I were to look at this reaction and...

If I understand what you are saying correctly, I believe it would be: [A,B]^T=[A;B] [what matrix]⋅[A;B]=Acos(x)-Bsin(x) [cos(x),0; 0 -sin(x)]⋅[A;B]

Ahh, okay. This is starting to make more sense. So since we are using sin(x) and cos(x) as our basis functions, and we are operating on them, we just differentiate each piece and multiply by i. I understand that the inner product space defined is made from the linear combination of sin(x) and...

I believe I understand what you are saying, which is the inner product space is made of up all linear combinations of sin(x) and cos(x) which, like you said, is a function of the form f(x)=Asin(x)+Bcos(x). I am assuming A and B can be anything? complex or real? That makes sense to me, I went on...

(scroll to bottom for problem statement) Hello, I am wondering if someone could break down the problem statement in simpler terms (not so math-y). I am struggling with understanding what is being asked. I will try to break it down to the best of my ability Problem statement:Consider the inner...

First, thank you for your response. Although I am still a bit confused, I am making some sort of progress. Let me stick with the example quoted and go a bit further with it. So my initial operator A is acting on some function f(x) and when it acts on that function it gives us...

Oh wow, okay so I was wrong again! thank you. So since our initial operator, A, takes a function and takes the partial derivative of it first. So for sum of two functions (f(x)+g(x)) we are taking the partial derivative of this entire quantity, not each individual part. so it would then look...

Okay so here is my new attempt at the whole problem: Complete question attached. The two properties I need to fulfill are: A(f(x)+g(x))=A(f(x))+A(g(x)) A(cf(x))=cA(f(x)) first example: A(f(x))=(∂f/∂x)+3f(x) A(f(x)+g(x))=(∂f/∂x)+(∂g/∂x)+3f(x)+3g(x) A(f(x))+A(g(x))=(∂f/∂x)+3f(x)+(∂g/∂x)+3g(x) to...

I think I get it, so our initial equation: A(f(x))=(∂f/∂x)+3f(x) is defining what the operator A does. And what it is telling us is that A, the operator, takes a function and does two things to it: 1. it takes the partial derivative of the function, and 2. adds to it 3 times the initial...

Do you mean the result of A on a function is to take the partial derivative of the function?

Hello, I am struggling with what each piece of these equations are. I generally know the two rules that need to hold for an operator to be linear, but I am struggling with what each piece of each equation is/means. Lets look at one of the three operators in question. A(f(x))=(∂f/∂x)+3f(x) I...

No, I did forget/didn't understand where to put the other Q's at that point