Recent content by CptJackWest

But won't it integrate differently because it is in the formula x is the same inside the cos as well as in front. But in my equation I have a t and a t+2. xcos(ax)= 1/a^2(cos(ax)+ax*sin(ax)) | | a(n)=2/4*Integration[(t+2)cos((n*pi*t)/2)dt +...

Thanks for the help, equivalent formula for xsin(ax)= 1/a^2(sin(ax)+ax*cos(ax)) But what do i do with the t+2 out the front of the cos((n*pi*t)/2). That is the bit i need help with!

Homework Statement For the function f(t)={t+2, -2<t<0 {2, 0<t<2 {f(t+4) all t Homework Equations a(n)=2/T*Integration[f(t)cos(n*w*t)dt] b(n)=2/T*Integration[f(t)sin(n*w*t)dt] xcos(ax)=...

Thanks for the help I have found the H values and such. But wondering what formula I would use to put in the values. That is where I am getting stuck. Cheers

I know the answer is 6328kW, I just not sure on how the book came up with that answer. Can anyone help? An isentropic steam turbine processes 5 kg/s of steam at 4MPa,which is exhausted at 50 kPa and 100oC. 5% of this flow is diverted for feed water heating at 700kPa. Determine the power...

Thanks for the help, my teacher ended up explaining the whole thing to me and it is now a lot clearer. The speed was not the speed but the mass flow rate in litres per min. Thanks a lot for trying to help. cheers

Thanks for helping. This problem is from an experiment we did involving an engine.The speed was to stated but I am taking it as the speed of the shaft in the engine. That units that i wrote is what is the data sheet I was given. I did not like the look of them either, but I am now assuming that...

Homework Statement Calculate the Power, Efficiency, air to fuel ratio. torque-3.809Nm speed-3137.207 l/min T1 Temperature Exhaust=412.598degC T2 Temperature Ambient=19.141degC T3 Temperature Fuel=18.994degC dv/dt Volumetric Flow Air=109.954 l/min p fuel Fuel Pressure= 21.475 mbar...