Recent content by CrackerMcGinger

I want to answer this, but give me about...3-5 days to do some research.

I don't think you can buy meta materials yet. Based on what I have found, their most likely in the testing phase instead of developing phase. And no explanation is too long.

The Earth reaches for the moon as the moon reaches for the Earth. This can result in the crust being pulled apart due to tidal forces. To be precise, the moons surface should start to be pulled apart before the Earths crust is, but the result should be that the Earths crust starts to be ripped...

The moon is 238,900 miles (384,400 km) away from Earth, and it pulls on the Earth causing tides. Now close the distance to two meters. As the moon gets closer to Earth the Earth pulls on the moon more. Every action has an equal and opposite reaction. As the moon is pulling earth, the Earth is...

Well, to start you off I'm going to ask you something. How does the moon effect the earth?

And now is the time that I realize that I won't understand this completely until I take calculus in two years. But, and I only ask this because I am extremely interested in this, could you express this in terms so that a person who is taking geometry could understand. Now I am starting to...

Can you explain this in simpler terms and possibly give a specified example?

What is quantum gravity and how do you calculate the probability of where the particle is? I probably phrased the second half of that question wrong.

Who wants to bet that this thread will be on the "Interesting Discussions for the Week" list?

Can you rephrase that in simpler terms so I can understand what you said.

Hey! Can someone break a meter stick into three pieces 100 times for me and tell us the results! That would be great.

Well, what is the probability of a stick being broken into three unequal parts, one shorter, one longer, and another shorter again? If it has a probability that each point of the stick can be broken, then what's the probability that the stick can be broken into 3 equal parts?

Their is a decent probability that there is a higher number of balls than my estimate, I just don't have the knowledge to figure it out. If the same experiment were repeated several time then I would be able to form a hypothesis on the highest number of balls, for example; If you picked five...

I applaud Miss ProfuselyQuarky.

Since you give me 5 numbers, each of which represent the ball you picked at random, and the highest of all five numbers being 213, I personally can't find a higher number of balls that we know are their, and since both the GCF and HCF are 1 I will stay at my answer of 213.