ok thanks guys i have sovled that one,
BUT i have another question.
how do you work out the relative proportions of an alloy if you are given the co-efficient of that alloy?
cheers
C.
ok, so
L_L= diameter of lead at new temp
L_S= diatmeter of steel at new temp
at 70^oC L_o_L=1.0005L_o_S
so at the new temp,
L_S=L_o_S+ \Delta L_S =L_o_S+ \alpha_SL_o_S \Delta T
and
L_L=L_o_L+ \Delta L_L =L_o_L+ \alpha_LL_o_L \Delta T
and we want L_S=L_L
so...
OK, I have tried, but my maths is not very good. Can you give me a hint please? So far I have got the same point but I am not sure how to work the equations.
Thanks
Hi guys and girls,
I've been going thorugh some problems in cutnell & johnson on heat and temperature and I have become stuck on this question. Can anybody help with this? Its from Cutnell and Johnson 5th p375 Q18*.
A lead sphere has a diatmeter that is 0.05% larger than the inner diameter...