Recent content by crazy-phd
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Graduate Fourier Transform of non-centered circular aperture
Thanks for the help. I also found this article describing the transformation in detail. Thanks again. -
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Graduate Fourier Transform of non-centered circular aperture
Thanks for your remark, but I'm afraid having a wave function with a unit is not the problem, but only the symptom. Many sources on the net [1],[2] calculate the Fourier transform of a circular aperture to be \begin{equation} \mathcal{F}(A) = \frac{J_1(2\pi Rq)}{Rq}, \end{equation} but... -
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Graduate Fourier Transform of non-centered circular aperture
Hi there, I have a little problem in wave optics: I have a wave function \psi_{ap} that depends on some geometric parameters, but that has no units itself (as one would expect). But unfortunately when I calculate the Fourier transform of this wave function the Fourier transform has a unit... -
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Graduate 3D Schrödinger Equation for a magnetic vector potential in cylinder coordinates
Your equations can be solved without big problems: \Lambda(r,\,\theta,\,z) = \frac{1}{2}r\theta^2+\left\{\begin{array}{cc} \frac{2k_1\mathrm{ln}(r)}{\theta(\theta+\pi)} & r>r_0\\ \frac{k_2r^2}{\theta(\theta+\pi)} & r<r_0 \end{array}\right. The gradient of this expression does not show a...- crazy-phd
- Post #9
- Forum: Differential Equations
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Graduate 3D Schrödinger Equation for a magnetic vector potential in cylinder coordinates
That's exactly what I thought when I started out with this adventure: "just" integrate. Yes, it would be helpful for \Lambda to be continuous at r=r_0 But one has to keep in mind, that I'm talking about a 3 dimensional vector potential \vec{A} and a scalar function \Lambda of 3 variables...- crazy-phd
- Post #7
- Forum: Differential Equations
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Graduate 3D Schrödinger Equation for a magnetic vector potential in cylinder coordinates
It's me again. After checking back to some books I decided to perform a Gauge Transformation of the form \vec{A}' = \vec{A}+\mathrm{grad}\Lambda=0 such that the solution to the initial Schrödinger equation becomes \psi = \psi'*\mathrm{e}^{\frac{ie}{\hbar c}\Lambda}, where \psi' is the...- crazy-phd
- Post #5
- Forum: Differential Equations
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Graduate 3D Schrödinger Equation for a magnetic vector potential in cylinder coordinates
Hi Mat, as usual m,e and E are constants (mass, charge and kinetic energy of an electron). I did not bother to insert for A², but that would be equal to 1/r² or 1/r²_0 (r_0 is an arbitrary constant]. If you have any other regards why equation (8) should be wrong, please let me know. CU Andi- crazy-phd
- Post #3
- Forum: Differential Equations
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Graduate 3D Schrödinger Equation for a magnetic vector potential in cylinder coordinates
Hi there, during my work on my PhD thesis as an experimental physicist I ended up with a very theoretical problem: What does the wavefunction of an electron traveling through a magnetic vector potential look like? I chose a cylindrical coordinate system with a magnetic vector potential A...- crazy-phd
- Thread
- 3d Coordinates Cylinder Magnetic Magnetic vector potential Potential Schrödinger Schrodinger equation Vector Vector potential
- Replies: 10
- Forum: Differential Equations