\hat{1} + (-\mathrm{i} \hat{H} \delta t) + O(\delta t^2)=\hat{1} + [-\mathrm{i} \hat{p}^2/(2m) -\mathrm{i} V[\hat(x)]+O(\delta t^2)
I don't understand it. Why are there an equal?
That's a good answer for me. Finally, what is difference betweeen that action and this:
Action= ∫Ldt
where L is the lagrangian. Are there any differences?
Yes, of course:
"...Action has the same dimensions as Planck's constant, h. When the action is smaller or of similar size to h, quantum mechanics rules. When the action is much larger than h, quantum democracy gives way to the more rigid phenomena that we term classical mechanics. Thus...
Thank you. But I wasn't reading neither "old quantum theory" nor the "quantum chaos". I was reading about "quantum mechanics non-relativistic". I think the action is concerned with angular momentum. However, I'm not sure.
What does the word "action" mean in quantum physics?
Hi everybody,
I was reading about the application range of quantum mechanics. I found the effects of quantum mechanics are negligible where the action is on the order of the Planck constant. But, What does the word "action" mean?
Thanks