Thanks Arildno,
I have been thinking about this more clearly...
1. I know the cube is growing at 5in^2 per week.
2. This can be represented as 5x (where x is the week number)
3. I need to figure out the week where the length is 7 inches. Solving \sqrt[3]{5x} = 7 , I find that the...
Imagine a cube that 'grows' by five cubic inches per week. How fast is its surface area increasing when the length of one of its sides is seven inches?
I know that the derivative of volume (V) with respect to time (t) is 5, e.g:
\frac{dV}{dt} = 5
To calculate the surface area of a cube...
Thanks for the hints - reading up on polynomial division (which I wasn't familiar with) I have found that the factors are:
(t-4)(1/2t^2-3t-9)
However, (and I realize I'm getting slightly off topic here) how would I even arrive at (t-4) being one of the original factors. Using GCF I can...
Given:
s(t) = 1/2t^3-5t^2+3t+6
I'm trying to find all values of t where s(t) = -30
My first thought is to solve for 0 hence:
1/2t^3-5t^2+3t+36=0
I know the answers are t=4 and t=8.196 but I can't get to it...I'm assuming I need to factor this down but I'm can't see it. Any...