Recent content by crowdedscience
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Solving Tangent to Ellipse: x^2+5y^2=5, y=mx+c
sorry, I'm starting to feel stupid now, but I just don't see how (q(1+5m^2))^2=5m^2+1. Also I'm not familiar with fermat's approach, what does that involve?- crowdedscience
- Post #8
- Forum: Calculus and Beyond Homework Help
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Solving Tangent to Ellipse: x^2+5y^2=5, y=mx+c
ok, so I did y-y1=m(x-x1) y-q=-p/5q(x-p) y=-px/5q + p^2/5q + q y=(-p/5q)x + (p^2/5q + q) so then c=p^2/5q + q but then when I put that into c^2=5m^2+1, it isn't equal what did I do wrong? Thanks- crowdedscience
- Post #6
- Forum: Calculus and Beyond Homework Help
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Solving Tangent to Ellipse: x^2+5y^2=5, y=mx+c
the derivative of x^2+5y^2=5 was dy/dx=-x/5y- crowdedscience
- Post #4
- Forum: Calculus and Beyond Homework Help
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Solving Tangent to Ellipse: x^2+5y^2=5, y=mx+c
An ellipse has the equation x^2+5y^2=5 a line has the equation y=mx+c a) show that if the line is a tangent to the ellipse then c^2=5m^2+1 b) hence find the equation of the tangent parallel to the line x-2y+1=0 I tried to find the gradient of x^2+5y^2=5 at a point (x1,y1) and then put it...- crowdedscience
- Thread
- Ellipse Tangent
- Replies: 10
- Forum: Calculus and Beyond Homework Help
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Charge on two suspended metal balls
oh wow, oopsies!- crowdedscience
- Post #3
- Forum: Introductory Physics Homework Help
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Charge on two suspended metal balls
Homework Statement Two very small metal coated foam spheres, each of mass 2.80x10^-6kg, are attached to nylon threads 45cm long and hung from a common point. When the spheres are given equal quantities of negative charge, each supporting thread makes an angle of 15 degrees with the vertical...- crowdedscience
- Thread
- Balls Charge
- Replies: 5
- Forum: Introductory Physics Homework Help