Recent content by crowKAKAWWW

Ah ok, So because of the denominator \sqrt{1-x^2}} In order to get a real number... x^2 < 1 So the limits would be (-1, 1), added together gives me my convergence to 0, is that it?

Hi, I need to determine whether this improper integral converges or diverges \int_{-1}^{1} \frac{x}{\sqrt{1-x^2}}dx The original function DNE at -1, 1 so I split the limits \int_{-1}^{0} \frac{x}{\sqrt{1-x^2}}dx \ + \ \int_{0}^{1} \frac{x}{\sqrt{1-x^2}}dx I've...