Recent content by Crusaderking1

This was a lab experiment, and these values were measured or given. the two coils were set up with an iron core and were faced toward each other with 2 voltage probes acting as a voltmeter. Later on for a separate trial, we had the iron core placed right through the transformer with still two...

Ok, I have a primary and secondary coil. I set up a transformer between them. Each has 400 turns of coil(N). The primary coil produces a potential difference of 2.988 V. The secondary coil has a potential difference of 0.0551 V. For the efficiency, I used the equation (Np*Vs)/(Ns*Vp) * 100%...

Alright, thank you very much for the detailed and well-written response. I have a much better idea on what is actually happening.

Homework Statement A straight, nonconducting plastic wire 8.00 cm long carries a charge density of 125 nC/m distributed uniformly along its length. It is lying on a horizontal tabletop. A) Find the magnitude and direction of the electric field this wire produces at a point 5.50 cm directly...

That does make sense, thanks for your help.

Thank you very much for your informative and helpful feedback. You also cleared up any confusion I had on the phases.

Homework Statement A 2.30 kg mass on a spring has displacement as a function of time given by the equation x(t) = (7.40 cm)cos[(4.16)t-2.42] a) Find the time for one complete vibration. The back of the book had this same equation but a different mass, so I was able to figure out...

its not in static equilibrium, but its not touching the floor because the ruler is on a stand. I'm suppose to find the "other forces"(not the weights I added) before I calculate the static equilibrium. So I need the torque value 1 + torque value 2 + other forces. There are two weights on the...

Sorry, the mass of the meter stick is 0.0836 kg. Well, I don't understand how inertia would tie in with finding the torque of the other forces besides the weights on the tension. Wouldn't it just be mass of meter stick, the distance between the pivot and the center of mass, then to find...

Question on torque(center of mass being important I think) Homework Statement I have a lab report due tomorrow, and I have it all done except one calculation, but it confuses me. The center of mass on my meter stick on a stand is 50.1 cm, or .501 meters. For part B, we changed the...

For part D. I received the acceleration of the radius by multiplying 0.887 rad/s^2 by 2pi. =5.73 rad/s I received the tangential acceleration by the change in speed of (2.56 rad/s)^2 multiplied by the radius of 0.355 m. = 2.195 rad/s. (5.57)^2+(2.19)^2 and the square root = 5.99 rad/s which...

Ok, thank you guys for all the help! much appreciated.

The angular velocity w = w0 + a*t where w0=0.23*2*Pi rad./s also where 'a' = 0.887*2*Pi rad./s^2 At t=0.192, w(0.192) = 0.23*2*Pi + 0.887*2*Pi*0.192 =2.5 rad/s On part B, I need to plug in time(0.192 s) where I plugged in initial angular velocity? For, C, should i be using the radius of .355...

Homework Statement An electric turntable 0.710 m in diameter is rotating about a fixed axis with an initial angular velocity of 0.230 rev/s. The angular acceleration is 0.887 rev/s^2. A. Compute the angular velocity after a time of 0.192 s. B. Through how many revolutions has the blade...

I changed Abigail's final velocity to negative since it has direction. It worked. Thanks therealnihl.