Recent content by crystal91

:confused:,so i would do it like this :1/2integral sin(2ax) which would be -1/2cos(2a)*1/2 so then the answer would be -1/4acos(2a)? and forget about this -cos(a+b)/2(a+b)-cos(a-b)/2(a-b)?

then what do i do with this formula -cos(a+b)/2(a+b)-cos(a-b)/2(a-b)?

do u mean to say set b as a in the formula sinax cos bx,so it would be sinax cosax??

Homework Statement how to guess the value of the integral sinax cosbx and for what values of a and b is your formula valid? Homework Equations used the formula 1/2[(sin A-B)+sin(A+B)] The Attempt at a Solution this is what i got -cos(a+b)/2(a+b)-cos(a-b)/2(a-b).after that to guess...