Recent content by Curd

You can solve it for zero, which is what is meant when typically when people speak of solving equations. You can also solve it for many other numbers.

I'm pretty sure you can factor a x^5 or greater polynomial out with a combination of rational zeros theorem, bounds on zeros theorem, factoring and long division. The book has been making me do that in this section. It would just be nice if it were cleaner. Well, I've only had to do one...

Then it seems a rather clumsy thing to use for solving polynomials. Is there a better theorem out there for this purpose?

When solving 3x^3+4x^2-7x+2 the rational zeros theorem says there can only be a possibility of zeros at plus minus 1, 2, 1/3, and 2/3 but for some reason a zero appears at about -2.4 (or more accurately -1-squareroot of 2). How can this be? It states that if there are any zeros they will...

What book would be good for real analysis?

what are good books on this?

So I do need more than algebra to understand it and this is why they didn't show proof of it?

here

I've come across the bounds on zeros theorem in my algebra book, but they don't seem to try to offer proof for it. Does this proof require calculus?

the section of the book I'm using.

i like how the book doesn't introduce the rational zeros theorem until the next section after this one. what's up with that? and why are there so many names for the same theorem?

for some reason i keep getting x^2-2x-3 with a remainder of 2 (what do you do with remainders anyway?). the book gets x^2-4x-1

the thing is i just don't like synthetic division. it feels uncertain to me. i prefer to do it the long way. I just don't get why my long way didn't work. Ah, now i see the x+1 thing. how did they know to use that? and how did you get the x+1 thing? how is it that when looking at the...

x^3-3x^2-5x-1 ?? x^3-3x^2-5x-1 apparently the book solved it by dividing it by -1 with synthetic division. i don't like synthetic division and tried to use -x with regular division. it did not work out. how does one solve this without using a calculator? please explain why...

it's a lot better. i think the rest I'm going to have to come to on my own.