Recent content by curiousjoe94

PV at the start is going to be the same as PV at the end, right? Going back to what I said about ratio of volumes, what I originally meant to say was that the ratio of volumes to be equal to the ratio of pressures, here's what I mean: volume of hand pump / volume of container equals...

didn't Tsny say that this method can't be used because volume is dimensionless?

judging from the full ideal gas law he's given (PV = nRT) He said that the number of moles of the gas (n) in the container increases by 25% (not entirely sure how he worked this out) Therefore if V stays the same, then pressure must increase by 25%

I'm not told the initial pressure of the air in the pump. I guess I'm going to have to assume that its the same as the container. I guess chestermiller's use of full ideal gas law works, but I find it strange because this question is on the first page of this gas section on the textbook...

Oh I see, so pressure would increase by 25% as well. So the new pressure would be 101kPa + 101*0.25kPa?

how is this done? I know that initial pressure is 101kPa and like you said final pressure would be Pf + 101kPa initial and final volume would surely be the same, right? boyle's law is PV = constant

For this, do I just find the ratio between the volumes of the hand pump and the container, and then equate this ratio to the initial pressure (before the pump of air was put into the container)?

Homework Statement A hand pump of volume 2.0 x 10-4 m3 is used to force air through a valve into a container of volume 8.0 x 10-4 m3 which contains air at an initial pressure of 101kPa. Calculate the pressure of the air in the container after one stroke of the pump, assuming the temperature...

If that's the case, then it makes sense having point P lying below both those charges.

Heres the question: Two charges (one is +4μC, the other is -8μC). They lie on 80mm apart, so you can imagine that the +4μC charge is on the left and the -8μC is on the right. Point P is equidistant from the two charges, draw two arrows at P to represent the directions and relative magnitudes of...

I get it now. You say there's a minimum between the two charges, would it correct to assume this would never be zero?

Say you have two point charges, both are positive. Would I be correct in thinking that electric potential (V) would be highest at some point along the line between those two point charges, and then decrease as we get closer to each of the charges?

Apparently for emf to be induced in a coil, the magnetic field (or part of it) has to act along the normal to the coil face. So does this mean that the coil moves side-ways through the magnetic field? where instead of moving through its length (its longer side), it moves through the coil face...

Ok so it would be: E'd + E30 - Ed = 2v where E' refers to the 15μC charge and E refers to 30μC charge, still not sure where to go from here.

quick question, if the charge Q is negative, would the electric potential value be decreasing the closer you get to Q? whereas with a positive charge, electric potential increases further inwards towards it, right?