Recent content by CyberneticsInside

Thanks, yes thay assume c = 1000 m/s.

Hello, I am reading a book about simulation, modeling and automatic control. In a chapter about hydraulic transmission line, a pipe's "bandwidth" is mentioned. Contex: "Long pipes are used in large hydraulic installations where pipes of length up to 10 m are not uncommon. Moreover, in offshore...

Homework Statement [/B] When asked for the bouancy of a hollow cylinder, containing air, submerged in ocean water. outer radius R. Length of cylinder = L The Material of the cylinder is neglected. I'm thinking the Bouancy (Force) = ρ ⋅ g ⋅ v where v = LπR^2 and therefore F = ρgLπR^2 But the...

Thank you :)

Hello, does anyone know a good resource for video lectures on the subject of fluid mechanics?

Yeah, obviously :p

Oh yeah. I did not think of the rod. Sounds interesting to try tough (remive the rod)

I don´t follow when you say rockets at sea level has no speed. What do you mean ? And I believed that the center of pressure is further to the ground than the center of mass, in new years rocket. I saw an old picture of a ¨Front wheel´´ driven rocket, but it was highly unstable, and crashed...

But at sea level, a rocket may be stabilized with finns on the body? (Fixed motor)

oh i see, thank you.

Ok, thanks for the response. So the stability is caused på some kind regulator, f. instance a PID? Meaning a fixed motor will be un-stable?

Hi, I can´t understand how a rocket is not flipped over by the thrusters (especially without finns). I know this is a general misconception of how a rocket works, but it seams intuitive that it would behave like a inverted pendulum, since the force works below the center of mass, of the rocket...

Ah, found it ! So the answer would be \dot{x} = - \frac{g}{C}x + \frac{1}{C}u

Ok, I think I got it. C dx = u dt - g(x-v)dt x'(t) = - (g / C)x + (1 / C)u Just an additional question: Is there some better way to type in equation, like Latex or similiar?

Ok, thanks.