Recent content by D.R.

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    Solve Neutrino Oscillation Unit Conversion Problem

    Homework Statement I doubt that my problem is supposed to be in the Advanced Physics forum, but the subject is advanced. Okay, my problem is pretty stupid. The assignment is deriving a probability using some approximations and such, for 2-neutrino oscillation. I can do the entire calculation...
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    Four gradient operator, covariance/contravariance

    Yep, that's the correct way.
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    Locus of Z for Z^2= (1+z)/(1-z) when |z|=1

    Hey, no problem. It's my mistake screwing up the hints for not understanding the concept of this question.
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    Locus of Z for Z^2= (1+z)/(1-z) when |z|=1

    It's me that's confused by this assignment. But nvm, ignore my replies. They make no sense.
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    Locus of Z for Z^2= (1+z)/(1-z) when |z|=1

    I must apologize, I was completely wrong, offset values, etc. and there is one thing that must be wrong with this assignment or else it wouldn't make much sense. To correct: With 1 + z and 1 - z, the offsets are the same, +1, but they still describe a circle because |z| = 1. So basically...
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    Four gradient operator, covariance/contravariance

    You're overdoing it. I suggest you look at Ben's reply, which gives you the chain term you get from applying the chain rule as a result of changing the variables (this terms will turn out to be the metric for co- to contravariant and back (since it is its own inverse)). Also, the question only...
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    Calculating the Rate of Mass Falling Over an Area

    It's not purely to calculate the mass. It also determines the rate per unit time through an area S. So you can rewrite S and v as: Sv = S\frac{dr}{dt} = \frac{dV}{dt} , with V a volume The physical interpretation is that a volume V moves through an area S in dt time. See it as moving a cube...
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    Locus of Z for Z^2= (1+z)/(1-z) when |z|=1

    This problem requires a geometrical/graphical understanding before you can use any algebraic methods of solving it. I'm going to give you this insight, and the rest you can solve yourself. Your original try at a solution is not wrong, it just lacks an additional constraint. The complex number...
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    Four gradient operator, covariance/contravariance

    Hint: The differential of the scalar function is a four-vector, because the differentials are over time, x, y and z, but in contravariant notation. Try understanding how the covariant position compares to the contravariant position (it's pretty simple). Then use the chain-rule to rewrite the...
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