Recent content by damndamnboi

thx for telling me about the image not working, i have posted the question in typed form, please take a look. thx.

i would like to find the area bounded by the curve (((x^2)/(a^2))+((y^2)/(b^2)))=xy/(c^2) i used the substitution given x=(ar)cos(theta) and y=(ar)sin(theta) i get : (r^2cos^2(theta)+r^2sin^2(theta))^2=xy/(c^2) thus r^4=xy/(c^2) substituting x=(ar)cos(theta) and...

http://img243.imageshack.us/my.php?image=80830952sk3.jpg i did part 1 but the integral was very complicated after i subed in y=x^1/2. Can anyone help in evalutaing the first part. thankyou.

I see. I think it would be better if we use the change in K.E to calculate the workdone in this scenario

According to my physics textbook: Workdone=force x distance moved by object in the direction of the force. This is ridiculous in a scenario with no friction force. For example, an object of mass 5kg, in space with no friction force or gravitational force is accelerated from rest to a velocity...