Recent content by dana1

hey, question is attached thanks in advance!

f: (R*R)->R f(x,y)=x+y if I'm asked to write 2 right inversed fanctions of f. can I say that: f1: R-> (R*R) f1(x)= (x-1, 1) f2: R-> (R*R) f1(x)= (x-2, 2) because: f(f1(x))= f(x-1,1)=x-1+1=x well this does matches the definition of right inverse function but what bothers me I guess is...

hey Serena, thanks for answering. Yes I had a typo- I ment if q=t then p=t. my confusion is that she didnt say anything about all cases where p=t and c isn't the empty set. because see should prove this is correct for all cases not just one. am I correct?

hey all, I am currently studing logic and set theory. My professor solved this question in a way that seems quit strange to me- Hope you could be of help. I attached the question in image file so signs won't be lost