Thank you so much. It looks like I got up to the very last step before the discriminant...I just factored differently and canceled x^r in earlier steps. I think had I not been trying to find a way to algebraically cancel out ln(x) I could have had the solution by using the formula for roots of...
oops, i left out that last term, yes I got what you have for the second derivative.
But the issue still remains when I substitute it into the expression
I end up with a[(r-1)+r+(r)(r-1)ln(x)]+b[r(ln(x))]+cln(x)=0
after simplifying. the natural logarithm term is what's making it hard to get...
I'm having a lot of trouble with this problem. I'm also having a lot of trouble inputting it into LaTeX. I hope you can follow even though the markup isn't good.
I'm trying to find a formula for the general solution of $ax^2y''+bxy'+cy=0$ where $y=x^r\ln(x)$ when $(b-a)^2-4ac=0$;
using...