hmm
since we know L=Iw and since I=Mr^2/2, L = (wMr^2)/2=constant
and from thermal expansion equation, we know delta r = alpha*r0*delta T
we can then add r0 and delta r to find the new r
then we plug back into L = (wMr^2)/2
and from the conservation of angular momentum we know...
I got I = 1/2 mr^2
then L = 1/2 mwr^2
but what bout the L?
do i find the change in radius with the thermal expansion equation then plug that radius back into the angular momentum equation?
the only thing i can come up with is that the radius is constant but, wouldn't the wheel have to expand which would increase the radius for there to be a change in the angular velocity?
Homework Statement
A 28.4-kg solid aluminum cylindrical wheel of radius 0.41m is rotating about its axle in frictionless bearings with angular velocity w = 32.8 rad/s. If the temperature is then raised from 20.0 degrees celcius to 95.0 degrees celcuis, what is the fractional change in angular...