Recent content by darshanpatel

It is a y-intercept, so if it has a b, then it indicates a y intercept

It would be a straight line because when you plug in values for 'a' and 'b' they will add to for some 'x' such as 7x or something.

When all the variables cancel out, I believe it is a parallel line. f(x)=(a+b)x indicates a straight line, the two significant points have a slope of 2 between them with a y-intercept of 5. That is why I got f(x)=2x+5 at the beginning. But since it does not follow ax+bx, I tried a different...

I understand that in order to solve this, you need to use a system of equations buy I am getting confused with setting it up and solving it: x+4=y ax+bx=y 3x+2=y solving for 'y' x+4=3x+2 x=1 plug 'x' in one of the equations you get: y=5 plug 'x' and 'y' into ax+bx=y...

The two points it needs to go through is (-1,3) and (3,11) indicating a straight line. When the variables cancel out it indicates...? I don't recall or remember anything about learning that

When I try using a system of equations, it cancels all the variables out? Such as 11=(a+b)(3) (11/3)-b=a That cancels out: 3=(a+b)(-1) -3=a+b when you plug it in

That's what I thought it should be but it says ax+bx and I don't think it's possible with ax+bx

Homework Statement Find the values of 'a' and 'b' that make f(x) a continuous function. f(x) = x+4, x≤-1 ax+bx, -1<x<3 3x+2, x≥3 Homework Equations None The Attempt at a Solution I plugged -1 and 3 into their respective functions to get the points: (-1,3) and (3,11) (-1)+4=3 3(3)+2=11...

Thank you, that makes sense but what do you mean by monotonous functions? I remember learning about things such as sin and tan only go from pi/2 to 3pi/2 and cos is the other way, but I don't really remember.

I think we are going about this the wrong way. I know for a fact that it is not going to be in the first or second quadrant because the sin was negative. But I don't know weather it is in quadrant 3 or 4 because they both can have negative sines. It might have to do with ranges as you were...

What do you mean by angles? Also, why does it matter? There are multiple angles per quadrant from 30 degrees to 60 degrees to 45 degrees and so on for each quadrant. Also, the -5/8 doesn't have a special angle like 30, 60, 90 triangles or the 45, 45, 90 triangles

Quadrant 1: sin and cos are both postive Quadrant 2: sin is only positive, cos negative Quadrant 3: sin and cos are negative Quadrant 4: cos is only positive, sin is negative

I do not have any idea what you are saying, but from what you are saying, what would the quadrant be? You are talking about a range from -pi/2 to pi/2 but I don't understand what you mean. We are not supposed to be using calculators so I don't know. Also, we need to find answers such as a side...

Those two are equivalent because if you do sin45 it equals 1/(sqrt2) and if you do arcsin(1/sqrt2) it equals 45 They are inverse functions.

The problem gave that: theta= arcsin(-5/8) It wants us to find the other five trig function values. In order to do that, I turned the original function to sin(theta)= - 5/8 From there I was able to find csc(theta) to be -8/5. Using the pythagorian theorem I found the other side...