Hi,
For a school project I have created a system which applies an equal force to 4 objects of measurable friction. Each yields a frictional force of approx. 3N (calculated from F = μFNormal) when in motion - but I am not quite sure as to calculating the total frictional force the combined set...
I know this question is very vague, but my textbook, amongst various websites/videos, tend to discuss what a transistor does (amplify/control current) rather than how it does it. I know current IC and IE (collector and emitter current) are controlled/proportional to a base current that flows...
Ok, thanks for the feedback.
gneill's digaram is pretty much correct, except there is no resistor ('r' in the diagram). Are you suggesting that to find normalised voltage I can use the equation you stated, and then substitute that into I(normalised) = V(normalised)/R(normalised) to identify...
OK, just to clarify, I will re-discuss the concept of my experiment.
In an Extended Experimental Investigation (EEI), I am investigating the effects that wires of various resistivity have on current density. Four different wires were used in four different trials, iron, tinned copper...
Ok, so you are suggesting that to find normalised current (which is all I need for the current density equation), I can just divide the original current by the length of wire it was transmitted across to find A/m (amperes per metre), which is normalised current that standardizes all values...
That is correct. Multimeters were placed in such a way that they could measure both current and voltage. 4 trials were conducted, with a separate wire of varying length and resistivity used in each. I chose to use varying lengths as some wires with minimal length were producing imprecise...
For an experiment I am conducting in a grade 11 physics course, I am attempting to find the effects of resistivity on current density. To ensure accurate results, I attached, in separate trials, the maximum length possible of 5 different types of wire (with varying material composition but...