Recent content by daviddeakin
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Undergrad Puzzled about direct current and charge (flux)
Ah, so my mistake was to say "the charge at a given point", when it should be "the charge that has passed a point", which of course can accumulate indefinitely!- daviddeakin
- Post #4
- Forum: Electromagnetism
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Undergrad Puzzled about direct current and charge (flux)
This is a question that has kept me awake, trying to rationalise it: Current is rate-of-change-of-flux (or charge if you prefer, which is the same thing): i = dQ/dt Therefore, flux or charge is the time integral of the current. Q = ∫i dt Therefore, if you have a direct current, does...- daviddeakin
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- Charge Current Direct current Flux
- Replies: 3
- Forum: Electromagnetism
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Calculating drift velocity of electrons in a conductor
The amount of charge passing a point in the wire in time t: Q = NqvtA N = electron concentration q = electron charge v = drift velocity t = time A = cross-sectional area So: v = Q/(NqtA) But current is: i = Q/t so substitute this in: v = i/(NqA)- daviddeakin
- Post #2
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
I don't think it's statcoulombs- they're for the cgs system. Note that it says the flux is in coulombs for the SI system. I can see this is going to keep me awake for a while.EDIT: I emailed my lecturer about it, and he said: "It's the same. Intergral of _D_ is charge and integral of _E_ is...- daviddeakin
- Post #13
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
There's definitely nothing else at the end of sentence! The whole book (and indeed my lecture course) follows the same lines- flux is in coulombs. See Wiki, for example: http://en.wikipedia.org/wiki/Statcoulomb "An electric flux (specifically, a flux of the electric displacement field D) has...- daviddeakin
- Post #11
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
Hmm, I've been learning from a book which says: "Gauss' law states that the flux through any closed surface is equal to the charge enclosed by that surface." So I have been using flux in coulombs... What am I missing?- daviddeakin
- Post #9
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
Is (##\Phi##) the flux in coulombs? If so then (##\Phi_E##) would be the force between the plates wouldn't it?- daviddeakin
- Post #7
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
Intriguing! So the top and bottom capacitors are: C=εA/d = 4 x 8.85x10-12 x 2.0x10-4 / 4x10^-5 = 177pF The middle capacitor is: C=εA/d = 8 x 8.85x10-12 x 2.0x10-4 / 4x10^-5 = 354pF The total capacitance is: 70.8pF Charge on the top and bottom plates is: Q = CV = 70.8pF x 3V = 212.4pC...- daviddeakin
- Post #5
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
Hi Gneill, I have difficulty getting to grips with charge! If the top plate has some positive charge, then the bottom plate must have some equal negative charge. But the ones in between I'm not sure about! Do they have similar charge, alternating in sign, or simply zero charge? If it is...- daviddeakin
- Post #3
- Forum: Introductory Physics Homework Help
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Question on capacitance and electric fields
Consider a thin parallel plate capacitor of an area of of 2.0x10^-4 metres squared, with a thickness of 1.2x10^-4 metres. The top and bottom thirds of the capacitor are filled with a dielectric material with a relative dielectric permittivity εr1=4, and the central third, with another material...- daviddeakin
- Thread
- Capacitance Electric Electric fields Fields
- Replies: 12
- Forum: Introductory Physics Homework Help