Thanks to everyone who responded, especially Harrisonized, you were right.
Guess I was heading into the right path.
\int_{1}^ 0 t(t^4-1)2t dt
---> 2.\frac{t^7}{7}-2.\frac{t^3}{3} when integrated.
---> 0-\frac{6-14}{21} when variable substituted with the limits.
Homework Statement
To show that \int_{0}^ \frac{\pi}{2}\sqrt{cos\theta}sin^3(\theta) d\theta = 8/21
The Attempt at a Solution
The above expression was simplified as
\int_{0}^ \frac{\pi}{2}\sqrt{cos\theta}sin^2(\theta) sin(\theta) d\theta
\int_{0}^...