Recent content by deanchhsw

I see. So since N/L should be equal to n/v(delta t), with n being the answer to #b, doing the math n comes out to be N(v delta t)/L. I understand that now. But how, then, do you incorporate that to find the current I? OHH I solved my own question lol I = delta q/delta t, and delta q is...

My teacher recently gave me a task of relating magnetic forces to a beam of chraged particles moving in a straight line. To aid us in this, she also set up a guideline question, displayed below: The diagram below shows a beam of charged particles moving in a straight line with speed v. Each...

* This post was moved from the general math section by the poster himself There are two lines: L1 : x = 1 + 2t ; y = 2 - t ; z = -1 + 3t. L2: x = 2 - 3m ; y = 2m ; z = 1 - m. The problem states to find a general point on A on L1 and a general point B on L2, and then find the vector AB...

I mean this Here's what I meant by prodcut of direction vectors. direction vector L1 = (2,-1,3) direction vector L2 = (-3,2,-1) Thus D.V. L1 * D.V. L2 = det( i j k ) = (-5,-7,1) .........( 2 -1 3 ) ........ ( -3 2 -1 ) forgive me for using parenthesis where abstract value sign...

There are two lines: L1 : x = 1 + 2t ; y = 2 - t ; z = -1 + 3t. L2: x = 2 - 3m ; y = 2m ; z = 1 - m. The problem states to find a general point on A on L1 and a general point B on L2, and then find the vector AB from those points. Hence, Vector AB = ( -3m - 2t - 1 , 2m + t - 2, -m...

Oh. I never knew that there was an "elastic nature" for the potential energy. That's what I needed, thank you so much :)

Hello. I have troubles understanding how the pull-back car works in a physical sense, so I decided to post a question. By "pull-back" car, I mean one of thoese Hess Cars where you pull and the spring inside it shrinks and once you release the car the spring inside gives it a thrust forward...

As a physics student, I cannot be completely sure of answering this as some of experts in this forum would, but I'll do it anyway.. Don't be too mindful of the "3m/s" as a quantity. however, be mindful that it's moving at a constant speed. That means there is NO acceleration. As Dave...

To simplify the question, "All swinging objects, which differ only by their mass, show the same period." Why is this so?

Hello. I am having trouble understand the varying mass's effect on the period of a conical pendulum. Well, I understand that there is no effect. However, I am having trouble verifying that in a centripetal force equation for circular motion. Most generally, conical pendulum's centripetal...

I just wanted to post that thank you for being patient with me. In fact, I just realized how to solve this while I was coming back to clarify more things...sigh. I know, I know, I've never been more astounded by my stupidity.. teacher looked at me looking over your things and said "he's...

I'm really, really sorry, I still don't understand completely... I understand that acceleration(or force, for that matter) is a vector quantity, therefore those measurements can combine to do trig, etc... Force equals mass x acceleration, therefore the component of the weight going down...

I suppose it'd work this way, but the weight of the car cannot be measured; Although the answer is slightly ambiguous to me(my fault), at least I have a glimpse of how that'd work- the only problem is, we were not allowed to measure the mass of the cart, so the weight idea is gone. Only...

Hello, I've just joined this forum in hopes of finding some help to my physics problems. I usually can find out what to do by myself, but this problem seems to be requiring some advanced concepts...or it maybe is so that I'm just not using my noodle. A car is sliding down an inclined plane...