Recent content by Death-Unit

Nice. Inserting M+m then solving works. Thank you.

A mass m suspended from a spring of constant k has a period T. If a mass M is added, the period becomes 3T. Find M in terms of m.T=2pi(m/k)^(1/2) I know that the period varies as the square root of the mass so the mass M should be 9 times that of m. The answer is M=8m. I don't know why it is 8...