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Oscillations of a mass on a spring.

  • Thread starter Death-Unit
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  • #1
A mass m suspended from a spring of constant k has a period T. If a mass M is added, the period becomes 3T. Find M in terms of m.


T=2pi(m/k)^(1/2)



I know that the period varies as the square root of the mass so the mass M should be 9 times that of m. The answer is M=8m. I dont know why it is 8 instead of 9. Any help would be appreciated.

Thanks
 
Last edited:

Answers and Replies

  • #2
hage567
Homework Helper
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Your equation is a bit wrong (typo, maybe?), T=2pi(m/k)^(1/2). Have you worked it out mathematically? You will get M=8m. Remember that the total mass is M + m for when the period is 3T. Try to work it out.
 
  • #3
Nice. Inserting M+m then solving works. Thank you.
 

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