lim(x-->0) (1-cos14x)/(xsin(18x)), this gives 0/0
L'hopital's
lim(x-->0) (14sin14x)/(sin(18x) + 18x(cos(18x))), Gives 0/0
L'hopital's
lim(x-->0) (196cos(14x))/(36cos(18x)-324xsin(18x)) This gives 49/9 which is right...
Thanks, it seems I just screwed up the calculations. Sorry for the bother
Homework Statement
lim(x -->0) (1-cos(14x))/(xsin(18x))
Homework Equations
None? The Attempt at a Solution
The hint tells me to use L'hopital's rule through which I got
lim(x-->0) (sin(14x))/(18xcos(18x)+sin(18x)) (I factored out the 14 in the numerator)
That gave me a 0/0 so I did...