Recent content by dec1ble

you remind me of my friend phil wang - apply for princeton, duke, yale, harvard, stanford - may the force be with you my young patawan!

alright - so when i find the derivative of cos(w-1) - it will be -sin(1) - making the equation -sin(1)/cos(w-1), making -sin/cos = -tan(w-1) the answer thanks for all your guys help - much appreciated

if i have \frac{d}{dx} \ln u = \frac{1}{u} then i find d/dx cos(w-1) = -sin(1) then plug that into the u? so 1/-sin(1) - then I am stuck

the u would be the cos(w-1) right ?

see that's where I am confused...i believe i have to use the chain rule twice...but I am just confused on where to start and how to integrate in the ln

well the derivative of (ln x) is 1/x

I am presenting a problem in front of the class tomorrow and I am slightly confused on the steps for my problem. The problem is: Find the derivative of the given function f(w) = ln[cos(w-1)] The answer in the back of my book shows the derivative is -tan(w-1) - but I'm my steps aren't...

I am presenting a problem in front of the class tomorrow and I am slightly confused on the steps for my problem. The problem is: Find the derivative of the given function f(w) = ln[cos(w-1)] The answer in the back of my book shows the derivative is -tan(w-1) - but I'm my steps aren't...

stick to a community college...ivey leagues colleges are way overrated

Isnt this a physics forum? ban english! ^-^ :confused:

"i sold my car to have money to continue to study" Never would I resort to selling my ride...sighface

well being that it is the second best college in the US...do the math yourself...

i am having trouble with a fairly easy derivative - and was wondering if someone could show me the steps how to find this? Find this derivative algebraically f(x) = x^3 (x cubed) at x= -2 The answer in the back of the book says the derivative is 12 - but I did the work and got 4. Please...

hmm - can you simplify any of it for me in steps?

im trying to verify this identity - sin x + tan x / 1 + cos x = tan x - i get lost very easily and need the steps - can anyone help me? :yuck: