alright - so when i find the derivative of cos(w-1) - it will be -sin(1) - making the equation -sin(1)/cos(w-1), making -sin/cos = -tan(w-1) the answer
thanks for all your guys help - much appreciated
I am presenting a problem in front of the class tomorrow and I am slightly confused on the steps for my problem. The problem is:
Find the derivative of the given function
f(w) = ln[cos(w-1)]
The answer in the back of my book shows the derivative is -tan(w-1) - but I'm my steps aren't...
I am presenting a problem in front of the class tomorrow and I am slightly confused on the steps for my problem. The problem is:
Find the derivative of the given function
f(w) = ln[cos(w-1)]
The answer in the back of my book shows the derivative is -tan(w-1) - but I'm my steps aren't...
i am having trouble with a fairly easy derivative - and was wondering if someone could show me the steps how to find this?
Find this derivative algebraically
f(x) = x^3 (x cubed) at x= -2
The answer in the back of the book says the derivative is 12 - but I did the work and got 4. Please...