I=(2*m*(r+L)^2)/5)+(mL^2)/3
I=.0985
so
KE=1/2(.0985)\omega^2
I need to find omega so I can find kinetic E. Correct?
How does one find omega? Obviously gravity affects the speed but gravity isn't the same over the entire rotation so how does that work out?
Homework Statement
A cylindrical rod 26.0 cm long with a mass of 1.20 kg and a radius of 1.50 cm has a ball of diameter of 7.80 cm and a mass of 2.00 kg attached to one end. The arrangement is originally vertical and stationary, with the ball at the top. The apparatus is free to pivot about the...