Recent content by DeusAbscondus

Yes, Jameson, that is precisely what I had in mind: I want to be "assessed" online, in an ongoing way, and guided into specific areas for focused study on the basis of this assessment, all in the one package (as is the stated goal of ALEKS (https://www.aleks.com/about_aleks) Thanks kindly for...

My Question relates to Commercial Computer- or AI-assisted Math learning programs Can anyone recommend a competitor to ALEKS (which I used to use but gave up on when they revamped the lay out) Besides which, I have reason to believe that ALEKS may not be best value in computer-assisted math...

My Question relates to Commercial Computer- or AI-assisted Math learning programs Can anyone recommend a competitor to ALEKS, which I used to use but gave up on when they revamped the lay out (besides which, I have reason to believe that ALEKS may not be best value in town) Hello to everyone...

Thanks Sudharaka; great site. I might have to wait for a dedicated stylus to Latex hand-held device but meanwhile, for taking notes and good reading of script, Dem Portal is great. Cheers.

You are dead right: I did some research elsewhere and discovered that mint vim doesn't install a .vimrc (curious, huh?) Anyway, I will file this away in a little folder I have reserved for same, and when it comes time to have another shot at building latex for vim, it'll be there to offer...

Re: How to use Taylor series to represent any well-behaved $f(x)$ That makes sense. Meanwhile, I've been plugging and chugging a few simple polynomial functions through the T. series: hehe! what fun! it works! (*broadly grins) You made my day: not understanding was getting me down (as usual)...

Re: How to use Taylor series to represent any well-behaved $f(x)$ Okay, basically, I'm in the clear ... but just what is this "different x"? If it is distinct from the $x$ of my polynomial, by what principle/rule do I distinguish the two when I come to compute the polynomial? D'abs

Re: How to use Taylor series to represent any well-behaved $f(x)$ That has nailed it for me Bacterius! Mightily obliged to you. As per usual, the problem has vanished under the gaze of fresh eyes. (Going now to chew on this strong meat with a cup of medicinal wine "to aid the digestion")...

Re: How to use Taylor series to represent any well-behaved $f(x)$ Beautiful to read! Thanks kindly Bacterius. But how would this work for a polynomial? I mean, wouldn't the evaluation $x=0$ lead to "zeroing" all the co-efficients and resulting in non-sense? If I take the case of $y=x^2+2x$ is...

Does one assess $x$ at $x=0$ for the entire series? (If so, wouldn't that have the effect of "zeroing" all the co-efficients when one computes?) only raising the value of $k$ by $1$ at each iteration? and thereby raising the order of derivative at each...

Thanks David, sorry about missing this response of yours. Vim is working like a charm for me, in command line. But do you think I can find the 'rc" file! It just doesn't seem to be there. I did, however, find this and thought I would try your patience by sending it in case it provoked any...

Hi folks, Could someone please tell me how I can clean this up, $\Sigma_{k=0}^\infty$ placing sub-script and super-script directly below and above $\Sigma$ respectively? Here is the raw code I used to get the above faulty text: \Sigma_{k=0}^\inftyThanks kindly, Deo Abscondo

Hi folks, If $e^x= \Sigma_{k=0}^\infty \frac{x^k}{k!}$ what do I evaluate $x$ at? How does the sigma notation tell me what to do with $x$? $$e^x= \Sigma_{k=0}^\infty \frac{x^k}{k!}\ = 1+x+\frac{x^2}{2!}+\frac{x^3}{3!}+\frac{x^4}{4!} ... \text {ad infinitum}$$ Sorry, I just realized my error...

LInux MInt 14 (Nadia) On Dual Core 1.37 4GB memory

Hi folks, $\text{ Here is the problem: }$ $\text{ Given that } cosA = -\frac{1}{4} \text{ and given that A }$ $\text{ is an angle between 90 and 180 degrees, then find: }$ a) $tanA$ and b) $sinA$ $\text{Here is my working out: }$ $\text{1. Since A is in the second quadrant, then tanA...