Recent content by Dew.J

Please explain where F=GMm/r^2 provides a rotational force. I see one dimensional movement in the r direction no theta involved. Irregardless of the fictitious force issue, my example still stands.

Gravity is purely a function of Mass and Distance based of its universal form. The centripetal force you speak of f = mv^2/r is a fictitious force. Meaning it is not true force. That formula was derived such that Newtons laws would work with circular motion. Probably doesn't answer your question...

C should be higher, since the velocity at C is less than the velocity at A you can infer that the car has passed it's initial point. Since it had an initial velocity of 20 m/s you would expect it to have a final velocity of 20 m/s when it reached the dame height on the other side. however, the...

Conservation of energy 1/2mv^2 + mgh = 1/2mv^2 + mgh you can drop the mass out since the mass is constant. thus, 1/2v1^2 + gh1 = 1/2v2^2 +gh2 Use a and b to find the speed at b, and then b and c to find the height at c

No acceleration implies that Fk = Fx Breakinging F down into it's components we get: Fcos\theta = Fx Fsin\theta = Fy Now setting Fx = Fk = (2kg * 9.81 m/s - Fy) Now you have three equations and three unknowns and can solve for F. I made +y in the direction of gravity...

Homework Statement Using only the information above (previous problem), what is the line width of the spectral line representing the 5 to 2 transition in H (hydrogen) Homework Equations Given Data: lifetime of n = 5 is 7.52ns lifetime of n = 2 is 1.38ns Thus, total t...