Recent content by diffidus

I feel a bit like a bad penny now but I have looked over my calculation and I can now see where the minus signs come from. The problem is given in terms of a boost in the z-direction: From this we get: Which can be calculated independently using: Using this second method the minus signs in...

Apologies - I looked back at my calculation and it appears that I managed to get a minus sign in there. I have redone the calculation and I now get positive values and so I am now completely on the same page as you. In the matrix quoted in the book - it must be a typo. Thanks very much for your...

That would be great, but I am not certain since in the book that I refer to, it also gives the product involving εε in terms of a projection operator: and that When I use this method it gives the matrix including the minus signs. So I am still not confident. Anyhow, thanks for your effort, it...

Hill So I think you got your result by using the previous example values for ε as you have said. Then, I assume you carried out the product sum with with λ =1,3. Thanks for this answer, it gets me closer but then there is still the annoying minus signs, which makes me think there must be...

Before boost we have Then using the Lorentz boost: I want to calculate: I tried multiplying the matrices together but I never get the stated answer which should be: