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continuation ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ Pt 3: How much dich. would be required to remove from 98.5% of A in a single extraction? 98.5% = 9.85g of total weight of A in dichloro wt. of A in Dich = (x)(y) = .985g x= x y = orig wt. of dich. z = x*y z= 10g wt...

is this method right>>?>?? Basic numbers : 10 g of A total 100 ml of H2O, 100 ml of dichloromethan ( Iwilll abbreviate as dich.) 10 g of A in 100 ml of h2o by a single extraction w/ 100 mL of dich.? if (x) g = the amount that stays in the water, 7.3(x)g of A must go into dich. phase...

Extraction efficiency problem PLease help... Homework Statement [FONT="Comic Sans MS"][SIZE="4"]The distribution coefficient, k = (conc. in CH2Cl2/conc in H2O), between dichloromethane and water for solute A is 7.3. What weight of A would be removed from a solution of 10 g of A in 100...