Recent content by dirtboi22

Just to clarify for everyone, I am using the equations: F=[weight/g]*[dV/dt] dt=[weight/g]*[dV/F] t=∫[weight/g]*[dV/F]

You are most definitely correct! I apologize, with it meaning weight and not mass, do my equations look correct?

I am looking for a way that involves graphing, such that the area under the curve is equal to time. I also forgot to say thank you to the ones that are taking there time to help me here!

Finding the time it takes to reach 55 mph on paper. You have the horse power, torque, transmission gear ratios of 1-5, rpm range, drive ratio, and primary drive ratio, and weight. You know Velocity=[(RPM*tire radius*2pi)/(Drive ratio*Gear ratio*Primary drive ratio*60)] which is velocity in ft/s...

I had spoke to one of my school advisers, who actually gave me this equation. It was very short and I honestly felt like they really didn't care. I had used this equation and graphed force inverse vs velocity, and the area under the graph had actually represented a fairly accurate time for the...

SteamKing, Mass/g is mass over gravity, It represents the weight of the entire machine on the the driving wheel, being that the driving wheel is the cause of acceleration? However Maybe this is not needed. This equation is actually the reason I posted this question, I am not sure if...

Problem statement, I am calculating the time it takes for my motorcycle to reach 55 miles per hour, through its engine Horsepower, Torque, transmission gearing, and sprocket gearing.(chain driven) I am using the equations: F=[mass/g]*[dV/dt] dt=[mass/g]*[dV/F] t=∫[mass/g]*[dV/F]...