Oh...I used the average velocity for inital velocity (that was a typo by the way, -250 m/s should have been -25/18).
But initial velocity is 10 km/hr, and thus 250/9 m/s ?
Acceleration: 0 - 250/9 m/s / .72 s = 38.58 m/s²
I think I may finally have got it.
Well, his average velocity would be half of the inital velocity? So 5 km/hr.
That means 5 km/hr = 5000 m/hr = 25/18 m/s
Time: 1 m / 25/18 m/s = .72 s
So it takes him twice as long.
And -250 m/s / 72 s = -1.929 m/s
A deceleration of 1.929 m/s.
Thanks for your patience.
Oh, of course, that was foolish. It's 25/9 m/s and thus .36 s.
Does that mean that the average deceleration is 7.716 ms/s ? Is that correct?
So his speed is changing? I have no idea how that affects my answer of 7.71 m/s.
I'd appreciate some help with this physics problem:
A car is traveling 10 km/hr and crashes into a tree. The driver is thrown 1 m forward. What is his average deceleration?
Here's my work:
Velocity of driver: 10 km/hr = 10,000 m/hr = 250/9 m/s
Time: 1 m / 250/9 m/s = .036 s
So it...