I'm under the impression that the "rest position" is the equilibrium position for simply the spring, which is above the equilibrium position with the object attached. Still, I'm stumped...:frown:
EDIT: Wait, X is just .125, since it goes down .25 ... Yeah, wow...
I know mg=kx will somehow get me the answer, but I don't know why I can't see how. I realize that if you move the k over, you get mg/k, and m/k is in the period equation, but can't seem to get it. (also, the other way around for the omega equation).
I keep getting x in terms of f or T...
At equilibrium, the net force/acceleration is zero. I thought that was where you would say that mg=kx, but once again you don't have m or x, and I can't see multiple equations that could be used. I'm assuming since you don't need the mass, it will cancel out somewhere? Or do you not use it at...
The first thing I tried to do was find K, but for some reason cannot see what to do. (I'm usually relatively good with this stuff.)
Obviously you know that F=KX, and I thought that the F was the weight, but then you do not know the mass. If you could give me anything else, it would be...
Homework Statement
A massless spring hangs from the ceiling with a small object attached to its lower end. The object is initially held at rest in a position yi such that the spring is at its rest length. The object is then released from yi and oscillates up and down, with its lowest...
Oh, around the 0? Okay, 25, I got it. I thought you just took it to the bottom of the graph itself. Sorry for the stupid question, I am a freshman in high school in physics, so I don't pick up on this stuff easily by myself. Thank you very much. :biggrin:
It is simply a graph with straight lines. I thought that you simply break them up into rectangles and triangles and just add the areas..I really hope my simple math is just wrong, because otherwise I have no idea..Heres the direct link to the graph.
http://www.webassign.net/hrw/07_33.gif
I honestly feel like a complete idiot asking this, since I know it's really easy, but I just can't get the answer. The question is...
A 3.0 kg block moves in a straight line on a horizontal frictionless surface under the influence of a force that varies with position as shown in Figure 7-38...