Recent content by dizzle1518

Can anyone help me with the below question? for each of the following pairs of random variables X,Y, indicate a. whether X and Y are dependent or independent b. whether X and Y are positively correlated, negatively correlate or uncorrelated i. X and Y are uniformly distributed on the disk...

Homework Statement Suppose that X is uniformly distributed on (0,2), Y is uniformly distributed on (0,3), and X and Y are independent. Determine the distribution functions for the following random variables: a)X-Y b)XY c)X/Y The Attempt at a Solution ok so we know the density fx=1/2...

a bit yes would Y have a density or mass function? i thought mass since Y is defined over integers only. the fact that X is continuous and Y discrete is throwing me off somewhat.

so what would be the distribution of Y then?

got you. then picking up to what numbers you want to define the distribution of Y is up to the person solving the problem? i asked her the same thing, i.e. if the interval was (-infinity, y-1) and if the distribution of Y is phi(y-1), and that's what she answered

i think it just asks for the distribution of Y. How would you know which integers to specify anyway? I e-mailed my teacher and she replied with the below: "No, for every y the corresponding interval for x has to be (-infinity,[y]). The endpoint should be an integer." Does she mean it...

thanks. looks to me like the interval would be (-infinity, y-1). so the distribution of why would be \Phi(y-1). is this right?

In an analog to digital conversion and analog waveform is sampled, quantized and coded. A quantized function is a function that assigns to each sample value x a value y from a generally finite set of predetermined values. Consider the quantized defined by g(x)=[x]+1, where [x] denotes the...

would the answer to a modified version of this problem be 5/12? The urn contains 5 black and 8 red balls. You close your eyes and remove balls from the urn one by one without replacement. What is the probability that the last ball is black given that the 1st ball is red?

Hi all, I need help with the following problem: The urn contains 5 black and 8 red balls. You close your eyes and remove balls from the urn one by one without replacement. What is the probability that the last ball is black? This looks to me like it is a hypergeometric distribution...

thanks for all your help

ok i got λ equals 4 by setting it up in the following way: P(X = 1 ∩ X ≤ 1)=λe^-λ P(X≤1)=e^-λ+λe^-λ .8=λe^-λ/(e^-λ+λe^-λ) is this right?

But I am not calculating P(X≤1). I am calculating P(X = 1 ∩ X ≤ 1). you said to use P(A|B) = P(A ∩ B)/P(B). P(A|B) we have. that's P(X = 1|X ≤ 1) = 0.8 P(A ∩ B) = P(X = 1 ∩ X ≤ 1) = ? P(B) = P(X≤1)=? thus we have: 0.8=P(X = 1 ∩ X ≤ 1)/P(X≤1)...is this set up correct until now? if so...

ok so P(B) in this case is P(X ≤ 1) right? so doesn't that equal 1 since we are given that X ≤ 1? then we get 1*P(X = 1|X ≤ 1)=P(X = 1 ∩ X ≤ 1) =1*.8=P(X = 1 ∩ X ≤ 1) do i have this set up correct? what's the next step? I'm lost.

How did you get λ=4? P(X = 1|X ≤ 1) = 0.8=P(X = 1 ∩ X ≤ 1)/P(X ≤ 1). Since we are given that X is ≤ 1 then P(X ≤ 1)= 1 right? So that just gives us P(X = 1 ∩ X ≤ 1) = 0.8, which is basically saying P(X = 1) = 0.8 since x cannot be 1 and 0 at the same time. this sets up e^-λ=.8. But that doesn't...