Recent content by Djbari

ok. I had no clue. Thank you for explaining. I will find out the solution tonite in class.

I did have the 3160 squared and got 79,884,800...??

Problem: An experimental flywheel, used to store energy and replace an automobile engine, is a solid disk of mass 200.0 kg and radius 0.40 m. (a) What is it's rotational inertia? (my calculation says 16 kg.m) (b) When driving at 22.4 m/s (50 mph), the fully energized flywheel is rotating at...

Friction force = u*m*g ?

Hi Tiny -Tim, I didn't see the previous note matching the two equations. I have actually gotten to there but thought it was wrong - when maybe it's just I thought it stopped there. Am I right with (w*r)^2/r = 3.45...is it rads? How do I put that into F=ma?

I'm not seeing it. I only see a in terms that have t (time) and I don't have t. or in terms with F net or N and I don't have those do I?

not v. do I know a?

do I know a or v?

v = r(w)

ω = v^2/r ?

N would be the weight of the coin or m * a? accel is v^2/r?

why is ω - 1.11 π rad/s? thought it is accel? Do you mean the formula a=v^2/r ?

N is the pull inward? but there is friction holding it on the turntable. acceleration is the 1.11 pi rad/s? (I'm really struggling with this and appreciate your help)

N = ma N = m * 1.11 pi rad/s ?

My problem is: A coin is placed on a turntable that is rotating at 33.3 rpm. If the coefficient of static friction is .1, how far from the center of the turntable can the coin be placed without having to slip off? Am I correct with V= the 33.3 rpms? and that w (angular speed) =1.11 pi...