Recent content by dkhurana

What I meant is dTau is the same the same for all observers. I understand V0 transforms, but dTau doesn't transform from one observer to the other. They can all agree on what is dTau. What I meant by universal time is a time frame transform to that everyone agrees. From the transform equations...

Hi! No problem at all. That question was more for myself and I only accidently included it. I was mainly wondering why it is important that we take the proper time derivative of X that doesn't transform from reference frame to reference frame. But I think I get it kind of. If we have some sort...

Why is it so important that time doesn't transform? Ok so I am now realizing that there is a problem in defining the four velocity my way, assuming I make all the right corrections. The spatial components transform just fine with the relative velocity formula. But the first component by my...

I'm apologize for all my confusion, and I really appreciate everyone helping. I think I'm getting where you're coming at but I don't really understand it when you say "same thing" or the "same vector" but different terms. Would it be possible elaborate a little more on that? I think where I...

Ok so just to confirm, the whole reason we transform use 4 velocity is just to make it easier to transform velocity from one reference frame to another?

What I still don't understand is why is it so important that we have an absolute time T that we use dX/dT instead of dX/dt. I understand that using dX/dt won't transform under the lorentz transformation, but then why is it important that it does? Not all observers agree on the time taken between...

Thank you, understood! What I meant by "fast" is the quantity of difference in perceived time

I am so sorry for the unclear question. So my class is defining the four vector for an event as this X = (ct, x, y, z) (first is time * c, last 3 are spatial components) dX/dt = (c, dx/dt, dy/dt, dz/dt) V = dX/dT = dX/dt * dt/dT = (c/sqrt(1-v^2/c^2), v/sqrt(1 - v^2/c^2)) dt/dT is derived from...

So I understand that time is now part of the four vector, and so dividing delta X by delta t (time according to me), would produce just c as the first dimension of the vector, which gives us no intuition as to how fast time is moving for the observer, so is not useful. I understand why we...