Recent content by Dolan

1. J=F*t This could be rearranged as, J = Ft = mv - mu The first carriage, m1 : Ft=(m1)(4m/s) The second carriage, m1: Ft=(m2)(6m/s) So 4m1 = 6m2 or m1= 1.5m2 now m1u1+m2u2=(m1+m2)v so (4m/s)+(6m/s) =(m1+m2)v and incorporating the relationship that m1=1.5m2 then...

Sorry but I'm not really following. could you give me the formula I should use?

What's J?

Impulse = FT= m(v-u) = ΔP F is the force T is the time M is the mass v is the final velocity U in the initial velocity

Impulse? I'm not sure

m1 u1 + m2 u2 = m1 v1 + m2 v2 the two masses are the same?

Homework Statement A railway locomotive pushed a stationary wagon to accelerate it to a speed of 4.00 m s-1. The engine then applies an equivalent force over the same time on a second wagon to accelerate it from rest to a speed of 6.00 ms-1. The second wagon rolls down the track, collides with...