t^2=-2(y)/g
t^2=2(50)/9.8
t=3.19 s
y-50=v^2-(1.0)^2/2(9.8)
v^2-(1.0)^2 = (-50)*2(9.8)
v^2-1 =-980
V^2/-1=-980/-1
v^2=980
V=31.30 m/s
sir am i right ? regards on solving the problem ? thank you !
ah i see sir ! thank you. sir so i will disregard the illustration that our prof was made ? and i will focus in solving using the given value's in the problem ?
sir ! our professor says that it is always negative . so he is wrong ? and the right is -g=9.8 m/s^2 ? right ? thank you ! so sir we will disregards the illustration ?? and compute the final velocity just once ?
sir yes ! a= g . and the g is equals to -9.8 m/s^2
sir ! how many times should i compute for the time ? is it 1 time or 4 times ? base on the illustration ?
Homework Statement
A scaffolding is rising at 1.0 m/s when at a height of 50.0 m , then the man on the scaffolding drop a can. determine:
a. the time needed for the can to reach the ground .
b. what is the final velocity ?Homework Equations
note: g=-9.8 m/s
the letter o in the equation...
:( yeah we will use sin and cos. but my prob. is how to determine if when to use it in my 1st post kindly take a look in x solving for the x component they use sin and cos. my prob is that . how can i determine the function to be use
yes. a year a go. i know how to use the function but my problem is i don't know when to use the cos and sin function like in the x-component my prof use the sin function in computing the x component except on letter D and C . can you please help me how to analyze it . I'm confuse !
this problem was discussed by our professor . but I am a lil bit confused on it ! thanks ! help !
FIVE COPLANAR FORCES ACT ON AN OBJECT AND THEIR RESULTANT !
our prof use this formula !
Bx=Bsin(degree)
By=Bcos(degree)
ANSER:
VECTORS X-COMPONENTS...