Recent content by dopeantelope

following on from what was said previously, you've basically already done it with your drawing, as the H (lowest priority group) is pointing away from you.

Hi, Currently I am a second year studying to get my BSc in Chemistry. I have a huge interest in chemistry but in terms of my career I've discovered that I am really interested in psychology or neuroscience. I have a massive interest in not only the brain and how it functions but also the mind...

thank you so much for your help! @Borek

oh i see, so i need to add both together. 3.231 x 22.7 = 73.3437 0.2145 x 22.7 = 4.86915 73.3437 + 4.86915 = 78.2 dm3 @Borek

2.154 divided by 10, multiplied by 1 to give 0.2154 moles of nitrogen. as 1 mol of nitrogen = 22.7dm3 0.2145 x 22.7dm3 = 4.87dm3 @Borek

Sorry, so there are 2.154 moles of Na. So i divide this by 10 to get the number of moles of nitrogen? 0.2154 moles of nitrogen x 22.7 = 4.89dm3? @Borek

Okay so according to the first equation, there are also 2.1538 mol of Na. According to equation 2 there are 10 moles of Na. So i multiplied 2.1538 by 5 to get 10.769 moles of Na in the 2nd equation. I then divided this by 10 to get 1.0769 moles of nitrogen. So I multiplied 1.0769 by 22.7 to...

okay i see, so its just the ratio then. so now I've got 3.231 moles of nitrogen produced in the first step. do i multiply this by the 22.7 and get my final answer? @Borek

There is 2.158 moles of NaN3 initially.. which i calculated by dividing grams by the Ar. (could i just look at the equation for this value?) 3 moles of nitrogen produced in the first step. and 10 moles of Na ready for the second step. I am just using the equation for these values. But according...

A motor vehicle safety air bag contains sodium azide (NaN3) and potassium nitrate (KNO3). On impact, N2 is produced by the successive reactions: Reaction 1: 2NaN3—> 2Na + 3N2 Reaction 2: 10Na + 2KNO3—> K2O + 5Na2O + N2 What volume of N2 (in dm3) is produced from 140 g of NaN3 at 273K and 1 x...