following on from what was said previously, you've basically already done it with your drawing, as the H (lowest priority group) is pointing away from you.
Hi,
Currently I am a second year studying to get my BSc in Chemistry. I have a huge interest in chemistry but in terms of my career I've discovered that I am really interested in psychology or neuroscience. I have a massive interest in not only the brain and how it functions but also the mind...
Sorry, so there are 2.154 moles of Na. So i divide this by 10 to get the number of moles of nitrogen?
0.2154 moles of nitrogen x 22.7 = 4.89dm3? @Borek
Okay so according to the first equation, there are also 2.1538 mol of Na.
According to equation 2 there are 10 moles of Na. So i multiplied 2.1538 by 5 to get 10.769 moles of Na in the 2nd equation.
I then divided this by 10 to get 1.0769 moles of nitrogen.
So I multiplied 1.0769 by 22.7 to...
okay i see, so its just the ratio then. so now I've got 3.231 moles of nitrogen produced in the first step. do i multiply this by the 22.7 and get my final answer? @Borek
There is 2.158 moles of NaN3 initially.. which i calculated by dividing grams by the Ar. (could i just look at the equation for this value?) 3 moles of nitrogen produced in the first step. and 10 moles of Na ready for the second step. I am just using the equation for these values. But according...
A motor vehicle safety air bag contains sodium azide (NaN3) and potassium nitrate (KNO3). On impact, N2 is produced by the successive reactions:
Reaction 1: 2NaN3—> 2Na + 3N2
Reaction 2: 10Na + 2KNO3—> K2O + 5Na2O + N2
What volume of N2 (in dm3) is produced from 140 g of NaN3 at 273K and 1 x...