Recent content by Dorslek

Just wanted to clarify or add: For View B, it is a forward reaction of course, not an equilibrium. If (OH-) is implicitly interacting with the product (H3O+), the equilibrium shift is driven by the consumption of the product (H3O+) and the need to replenish those (H3O+). If (OH-) is...

So it seems I've been seeing two different ways of interpreting buffer solution reactions. One to me seems to work with Le Chatelier's Principle and the other doesn't. I am dropping a strong base, NaOH, into a weak acid/base buffer solution. View A: HA + H2O <--> (H3O+) + (A-) Reasoning: The...

Let's start with a generalized example: 3A + 1B -> 2C For the mole amount next to each molecule, am I always to consider these as relative to one another or absolute? Most of the videos I have seen are describing the above as "for every 3 moles of A and 1 mole of B you get 2 moles of C". I...

Ok, so then how is this optimal pressure met? The liquid in the evaporator boils into vapor. The hot air passing over the coil transfers heat into the liquid cause a phase change. Phase changes only occur once a saturation temperature is reached which means that the VP produced by the...

No, that was used as an example of external pressure being the atmosphere at sea level and water getting to 212F because now its VP is equal to the external pressure of the atmosphere so boiling is occurring. The question had to do with the refrigerant in a closed container being able to boil...

Thanks, I got all that but am still fuzzy on what I asked. At the exit of the evaporator coil, a refrigerant must be all vapor. In other words, a saturated temperature must be reached so that all the liquid refrigerant can turn into a vapor at the end of the coil when latent heat is added. The...

So I get that when the VP is equal to atmospheric pressure of 14.7 psia, if you will be at a saturated liquid and when more heat is added, it is latent head changing it to a gas. If however you are at a closed container where the can physically alter the "atmospheric pressure" in the container...

So pretty much, the liquid will keep boiling. In doing so, the vapor pressure will increase since more of the molecules will spring up into the closed container and increase the vapor pressure. At the same time though, the temperature of the liquid will be reduced due to a reduction in the KE...

The rest was helpful but can you clarify this part? Isn't the boiling going to reduce the temperature which will reduce the vapor pressure?

I understand the basic connections between vapor pressure of substances and how this effects their boiling points. However, I am a bit hazy on applying it to some real life situations so I want to give some examples to check where I might be going wrong in my thinking. 1. I have 70F water in...

Edited that out. I can then assume then if no units are mentioned, such as a pixel, that a partial derivative for z in x then is always going to be a very small change in X just like when doing a regular derivative?

For some non-linear 3D function, let's say I want to take the partial derivative for x where y is constant. Each point for Z will be different of course since it's non-linear. So let's say I plug in an X of 3 where Y is constant for some function and I get a slope of 5 as my answer. Is it...

Thanks. I was frustrated thinking that I didn't understand some crucial general concept but now am good.

1. In the Khan academy video I watched on partial derivatives, I understand absolutely everything except for the last 20 seconds which confused me. http://www.youtube.com/watch?v=1CMDS4-PKKQ Using the formula: Z = x² + xy + y² @z/@x = 2x +y x=0.2, y=0.3 2(.2) + .3 = .7 What...