Recent content by Dostre

Figured it all out guys. Ray Vickson thanks for an elaborate answer. I did similar calculation using combinations which gave me the same results. For part c, assuming there is a large number of rooms on each floor, question in part b is a subset of question in part in short. All answers may...

uhh guys. I am still cracking my head to come up with an answer to part c. I know this problem is very similar to the Birthday Problem. So one person is fixed. Now, there is a pool of six people that can be on my floor. I am stuck there.

I get what you are saying. In the problem statement they say that each floor has the same number of rooms. I would think this assumption holds for part b where they say at least 6 rooms per floor. Hence, I think it is reasonable to say the probability that one of the other 6 people are on the...

then the probability of at least one other person being on the same floor with me would be zero.

@D H I subtract those five rooms cause I try to calculate the probability of none of those six people being on the same floor with me.

(24/25)^6 oh ok makes sense. In this way I do not need to account for rooms at all then. For part c I am still struggling.

@DrClaude sounds good. What do you suggest should be my approach to part b then? An equation would be really helpful.

Homework Statement Seven persons are staying at a hotel. The hotel has twenty-five floors, each with the same number of rooms. Each of the seven persons has been randomly assigned to one of the rooms in the hotel. a. What is the probability that at least two people have rooms on the same...

If no one calls it is zero. Then, the payoff of the ith player is p^{n-1}*0+(1-p^{n-1})v . So for part b would it be correct to say that v-c=(1-p^{n-1})v ?

Homework Statement Consider the following social problem. A pedestrian is hit by a car and lies injured on the road. There are n people in the vicinity of the accident. The injured pedestrian requires immediate medical attention, which will be forthcoming if at least one of the n people call...

Already figured it out. Thanks anyway. The answer is here. http://www.reddit.com/r/HomeworkHelp/comments/1137pw/microeconomics_problem/

Homework Statement Hello. Thats my homework question, so any hints will be appreciated. Paul consumes only two goods, pizza (P) and hamburgers (H), and considers them to be perfect substitutes, as shown by his utility function: (, ) = + 4. The price of pizza is $3 and the price of...

Consider two agents (Pascal and Friedman) in a pure exchange economy with two goods and no free disposal. Pascal has a preference relation give by the utility function $$u^P(x_1^P,x_2^P)=a\ln (x_1^P)+(1-a)\ln(x_2^P-bx_2^F)$$ while Friedman's preferences are $$u^F(x_1^F,x_2^F)=a\ln...

Oh no they are not. My mistake. I was looking at another problem I am doing right now. It does not really matter whether they are negative or not for this inequality since the power of 2 makes their difference positive. But yeah they can be negative since they are distinct values of x and the...

That they are non-negative. I was working on this problem for a long time and I managed to turn the inequality: $$ \lambda(4-u^2)+(1-\lambda)(4-v^2)\leq4-[(\lambda u+(1-\lambda)v]^2$$ into $$\lambda (u-v)^2(1-\lambda)\leq0$$ Since 0<λ<1 the above inequality is true and the function...